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Can anybody help me solve this problem step by step​

Can anybody help me solve this problem step by step​-example-1
User Mayda
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Answer: The limit of
\( \sin^4(\pi (n + (1)/(2))) \) as
\( n \) approaches infinity is indeterminate. This means that the function does not approach a specific value as
\( n \) goes to infinity.

Explanation:

Given the function:


\[ f(n) = \sin^4(\pi (n + (1)/(2))) \]

We want to find:


\[ \lim_{{n \to \infty}} f(n) \]

Step 1: Understand the inner function

The inner function is
\( \pi (n + (1)/(2)) \). As
\( n \) approaches infinity, this term will also approach infinity. This means the argument of the sine function will take on increasingly larger values.

Step 2: Behavior of the sine function

The sine function oscillates between -1 and 1 for all real numbers. Specifically,
\( \sin(\pi (n + (1)/(2))) \) will always be -1 or 1 because:


\[ \sin(\pi/2) = 1 \]

\[ \sin(3\pi/2) = -1 \]

... and so on for every integer value of
\( n \).

Step 3: Raising to the fourth power

Regardless of whether
\( \sin(\pi (n + (1)/(2))) \) is 1 or -1, when you raise it to the fourth power, the result will always be 1. This is because:


\[ 1^4 = 1 \]


\[ (-1)^4 = 1 \]

Step 4: Conclusion

Given that for all integer values of
\( n \),
\( \sin^4(\pi (n + (1)/(2))) \) will always be 1, the limit as
\( n \) approaches infinity is also 1.


\[ \lim_{{n \to \infty}} \sin^4(\pi (n + (1)/(2))) = 1 \]

User Shishir Pandey
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