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3 votes
Find the difference quotient

f(x+h)-f(x)
h
f(x)=3x²-x-5
Simplify your answer as much as possible.
ƒ (x + h) − f (x) = 【
h
"
where h‡0, for the function below.
X
Ś

User MoRe
by
8.3k points

1 Answer

5 votes

Answer:
\( (f(x+h) - f(x))/(h) = -1 + 3h + 6x \) where
\( h \\eq 0 \)

Explanation:

To find the difference quotient for the function
\( f(x) = 3x^2 - x - 5 \), we'll use the formula:


\[ (f(x+h) - f(x))/(h) \]

Step 1: Find
\( f(x+h) \)


\[ f(x+h) = 3(x+h)^2 - (x+h) - 5 \]

Step 2: Subtract
\( f(x) \) from
\( f(x+h) \)


\[ f(x+h) - f(x) = 3(x+h)^2 - (x+h) - 5 - (3x^2 - x - 5) \]

Step 3: Divide the result from Step 2 by
\( h \)


\[ (f(x+h) - f(x))/(h) \]

Let's plug in the values and simplify.

The simplified difference quotient for the function
\( f(x) = 3x^2 - x - 5 \) is:


\[ (f(x+h) - f(x))/(h) = -1 + 3h + 6x \]

So,
\( (f(x+h) - f(x))/(h) = -1 + 3h + 6x \) where
\( h \\eq 0 \).

User Antonpv
by
8.6k points