16.8k views
1 vote
Let (7,-2) be a point on the terminal side of 0.

Find the exact values of sin 0, sec 0, and tan 0.
¹0 = 0
sin 0
sec 0
tan 0
= D
11
3 16
X
Ś

Let (7,-2) be a point on the terminal side of 0. Find the exact values of sin 0, sec-example-1

1 Answer

4 votes

Answer:

sin θ = -2 / √(53)

sec θ = √(53) / 7

tan θ = -2 / 7

Explanation:

To find the exact values of sin θ, sec θ, and tan θ when the terminal side of angle θ passes through the point (7, -2), we can use the Pythagorean Theorem and the definitions of trigonometric functions.

Let's denote θ as the angle formed with the positive x-axis.

To find sin θ, we use the y-coordinate of the point (7, -2) divided by the radius (distance from the origin to the point):

sin θ = y / r = -2 / √(7² + (-2)²) = -2 / √(53)

To find sec θ, we use the x-coordinate of the point (7, -2) divided by the radius:

sec θ = r / x = √(7² + (-2)²) / 7 = √(53) / 7

To find tan θ, we use the y-coordinate of the point (7, -2) divided by the x-coordinate:

tan θ = y / x = -2 / 7

So, the exact values are:

sin θ = -2 / √(53)

sec θ = √(53) / 7

tan θ = -2 / 7

User Ravjit Singh
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories