Answer:
Molarity =moles of solute ÷ volume of the solution(in liters) (1)
No. of moles of solute = given mass ÷ molar mass
Where,
moles= given weight /by molecular weight (2)
given mass =36.29 g
Molar mass of NaCl = 58.5 g/mol(23 + 35.5)
Substituting values in equation 2, we get
moles= 36.29 /58.5
=0.62 moles
volume of solution = 2.30 liters
substituting the given values in the equation 1, we get
Molarity= 0.62 / 2.30
=0.27M
Therefore; the molarity of NaCl = 0.27M.
Hope its helpful.