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Nter of a circle with the equation: x2+y2−18x−14y+124=0 x 2 + y 2 − 18 x − 14 y + 124 = 0

User Miscreant
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1 Answer

5 votes

Answer:

centre = (9, 7 )

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

use the method of completing the square to obtain standard form

given

x² + y² - 18x - 14y + 124 = 0

collect the x/ y terms and subtract 124 from both sides

x² - 18x + y² - 14y = - 124

to complete the square

add ( half the coefficient of the x/y terms )² to both sides

x² + 2(- 9)x + 81 + y² + 2(- 7)y + 49 = - 124 + 81 + 49

(x - 9)² + (y - 7)² = 6 ← in standard form

with centre = (h, k ) = ( 9, 7 )

User Domenic
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