Question

A towns population in thousands in 18 years is given by \( 17(t+x)^{18} \) where \( x \) is the growth rate per yetar. What is the population in 18 years if the growth rate is the following? Round you

Answer 1

Certainly! To find the population in 18 years we can substitute the given growth rate values into the formula \( 17(t+x)^{18} \) and calculate the result.

Let's consider the following growth rates:

- If the growth rate (\( x \)) is 0.05 (which means a 5% growth rate per year):

Population = \( 17(18+0.05)^{18} \)

= \( 17(18.05)^{18} \)

≈ 9419.76 (rounded to the nearest whole number)

- If the growth rate (\( x \)) is 0.1 (which means a 10% growth rate per year):

Population = \( 17(18+0.1)^{18} \)

= \( 17(18.1)^{18} \)

≈ 20942.57 (rounded to the nearest whole number)

- If the growth rate (\( x \)) is 0.02 (which means a 2% growth rate per year):

Population = \( 17(18+0.02)^{18} \)

= \( 17(18.02)^{18} \)

≈ 3463.94 (rounded to the nearest whole number)

- If the growth rate (\( x \)) is 0.15 (which means a 15% growth rate per year):

Population = \( 17(18+0.15)^{18} \)

= \( 17(18.15)^{18} \)

≈ 34798.7 (rounded to the nearest whole number)

Please note that these calculations are approximations and rounded to the nearest whole number.

Let me know if you need any further assistance!