Final Answer:
The height of the hill is approximately
feet.
Step-by-step explanation:
Let's denote the height of the hill as
and the distance from the person to the bottom of the antenna as

Using trigonometry, we can set up two equations based on the given information:
1. The tangent of the angle of elevation
to the bottom of the antenna is given by:
![\[ \tan(\theta) = (h)/(d) \]](https://img.qammunity.org/2024/formulas/physics/high-school/a9ngmva0ayqril6lpl124dfm4ktc7b6hc5.png)
In this case,

2. The tangent of the angle subtended by the antenna
is given by:
In this case,
and the height of the antenna is
feet.
Now, solve these equations simultaneously to find

![\[ \tan(25^\circ) = (h)/(d) \]](https://img.qammunity.org/2024/formulas/physics/high-school/1y205m5f7ieziqx0r0hzxiqt97orjz3uh1.png)
![\[ \tan(1.5^\circ) = (121)/(d) \]](https://img.qammunity.org/2024/formulas/physics/high-school/1a181ds24sxh3udno4wqcyens25hsepmmd.png)
Solving the first equation for

![\[ d = (h)/(\tan(25^\circ)) \]](https://img.qammunity.org/2024/formulas/physics/high-school/ak3shvib4oq2bcmwnbfk58z3gigoqudgcv.png)
Substitute this expression for
into the second equation:
![\[ \tan(1.5^\circ) = (121)/((h)/(\tan(25^\circ))) \]](https://img.qammunity.org/2024/formulas/physics/high-school/pbg7b2gj9z56wtjvswsfxtmsqhxoviw4j4.png)
Now, solve for

![\[ h = (121 \cdot \tan(25^\circ))/(\tan(1.5^\circ)) \]](https://img.qammunity.org/2024/formulas/physics/high-school/mhl9zshn20invjv667uw9fsdy4sofl654m.png)
Calculating this expression gives
feet.
Therefore, the height of the hill is approximately
feet.