Question

At constant volume, the heat of combustion of a particular compound is −3205.0 kJ/mol. When 1.579 g of this compound (molar mass =172.76 g/mol ) was burned in a bomb calorimeter, the temperature of the calorimeter, including its contents, rose by 5.995∘C. What is the heat capacity (calorimeter constant) of the calorimeter? calorimeter constant:

Answer 1

If the heat of combustion of a particular compound is −3205.0 kJ/mol then the heat capacity is -92707.4 kJ/℃.

Step-by-step explanation:

In order to calculate the heat capacity (calorimeter constant) of the bomb calorimeter, we can use the equation: q = C * ΔT, where q is the heat released, C is the heat capacity, and ΔT is the change in temperature. Rearranging the equation, we can solve for C: C = q / ΔT.

In this case, we know that q = -3205.0 kJ/mol (the heat of combustion) and ΔT = 5.995℃.

We need to convert the mass of the compound burned from grams to moles by dividing by the molar mass: 1.579 g / 172.76 g/mol = 0.00912 mol.

Now we can calculate the heat capacity: C = (-3205.0 kJ/mol) / (0.00912 mol * 5.995℃) = -92707.4 kJ/℃.