Final answer:
The E2 elimination of 3-bromo-2-methylpentane would result in the formation of three alkenes.
Step-by-step explanation:
In the E2 elimination of 3-bromo-2-methylpentane, three alkenes would be formed. This can be explained by considering the structure of 3-bromo-2-methylpentane.
3-bromo-2-methylpentane has a branched structure with a bromine atom attached to the third carbon atom and a methyl group attached to the second carbon atom. During the E2 elimination, the hydrogen atom on the adjacent carbon to the bromine atom is removed along with the bromine atom itself.
This results in the formation of three different alkenes:
- 2-methylpent-2-ene
- 2-methylpent-3-ene
- 2-methylpent-4-ene
Each alkene is formed due to the elimination of the hydrogen atom and bromine atom from different carbon atoms in the 3-bromo-2-methylpentane molecule.