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A beaker contains 44.7 mL of propane (C3H8, density is 0.500g/mL).

Determine how many C atoms this liquid contains.

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To determine the number of carbon (C) atoms in the given volume of propane, multiply the volume by the density to find the mass of propane. Then, divide the mass by the molar mass of propane to find the number of moles. Finally, multiply the number of moles by Avogadro's number to get the number of carbon (C) atoms.

To determine the number of carbon (C) atoms in the given volume of propane, we need to use the density and molar mass of propane. First, calculate the mass of the propane by multiplying the volume (44.7 mL) by the density (0.500 g/mL), which gives 22.35 grams.

Next, calculate the number of moles of propane by dividing the mass by the molar mass. The molar mass of propane is 44.10 g/mol (3 carbon atoms * 12.01 g/mol + 8 hydrogen atoms * 1.01 g/mol).

Lastly, multiply the number of moles of propane by Avogadro's number (6.022 x 10^23) to determine the number of carbon atoms. Since there are 3 carbon atoms in one molecule of propane, multiply the result by 3 to get the final answer. Therefore, this liquid contains approximately 1.354 x 10^23 carbon atoms.

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