149k views
4 votes
Which of the following wavelengths would create a standing wave pattern in a 25-cm open pipe?

User Cabadath
by
8.1k points

1 Answer

6 votes

Answer:

To determine the wavelengths that would create a standing wave pattern in a 25-cm open pipe, we can use the formula:

λ = 2L/n

Where:

λ is the wavelength

L is the length of the pipe

n is the harmonic number

In an open pipe, the fundamental frequency (first harmonic) occurs when n = 1. Therefore, for the fundamental frequency, we have:

λ = 2(25 cm)/1

λ = 50 cm

For a standing wave pattern to occur, the length of the pipe must be an integer multiple of half-wavelengths. So, any wavelength that satisfies the equation:

λ = 2L/n

where n is an integer, will create a standing wave pattern.

In the case of a 25-cm open pipe, the only wavelength that satisfies the equation is 50 cm, which corresponds to the fundamental frequency (first harmonic). Therefore, the answer is:

A. 50 cm

Step-by-step explanation:

User Taran Mahal
by
8.3k points

No related questions found