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4 votes
Simplify the following complex expression. Write your answer in standard form. (2+3i)(3-4i) Answer:

2 Answers

5 votes

Answer: 18 + i

Explanation:

Hello :) Our task is to simplify the following complex expression:


\sf{(2+3i)(3-4i)}.

We multiply two complex numbers just like we multiply any two binomials. We use the same method called FOIL.

FOIL

  • First
  • Outer
  • Inner
  • Last

First terms:
\sf{2*3=6}

Outer terms:
\sf{2*(-4i)=-8i}

Inner terms:
\sf{3i*3=9i}

Last terms:
\sf{3i*(-4i)=-12i^2}

We have:


\sf{6-8i+9i-12i^2}


\sf{6+i-12i^2}

Recall that i^2 = -1:


\sf{6+i-12(-1)}


\sf{6+i+12}


\sf{18+i}

User Mads
by
7.8k points
5 votes

Answer:

-12i^2 + i + 6

Explanation:

User Brian Vanderbusch
by
8.0k points

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