215k views
4 votes
A ball is thrown straight upward. It reaches its highest point

at 125 meters above the starting point and then it falls the same
distance back to its starting point. Neglecting air resistance, how
muc

User Jilly
by
8.4k points

1 Answer

3 votes
Thank you for your question. It seems like you would like to know the total distance the ball travels when thrown straight upward.

When a ball is thrown straight upward, it follows a parabolic path. The highest point in its trajectory is known as the peak or the maximum height. In this case, the ball reaches a height of 125 meters above its starting point.

Since the ball falls the same distance back to its starting point, we can conclude that the total distance traveled by the ball is twice the distance it reaches above the starting point.

Therefore, the total distance traveled by the ball is:

Total distance = 2 * 125 meters

By multiplying the distance reached above the starting point (125 meters) by 2, we find that the total distance traveled by the ball is 250 meters.

I hope this answers your question. If you have any further inquiries or need additional clarification, please feel free to ask.
User Jon Senchyna
by
7.8k points