Question

A given volume of neon passed through a small opening in 26.7s.

Under identical conditions, it took 38.5s for the same volume of a
hydrocarbon to pass through the opening. what is the molar mass of
th

Answer 1

To find the molar mass of the hydrocarbon, we can use Graham's law of effusion. By setting up a ratio using the effusion times of neon and hydrocarbon, we can solve for the square root of the molar mass of the hydrocarbon and then square the result to find the molar mass.

Step-by-step explanation:

The question asks for the molar mass of a hydrocarbon-based on the effusion times of neon and the hydrocarbon. The effusion time of neon is given as 26.7 seconds, and the effusion time of the hydrocarbon is given as 38.5 seconds. According to Graham's law of effusion, the rate of effusion is inversely proportional to the square root of the molar mass. We can set up a ratio using the ratio of the effusion times to find the ratio of the square roots of the molar masses:

(Square root of the molar mass of neon) / (Square root of the molar mass of the hydrocarbon) = (Effusion time of the hydrocarbon) / (Effusion time of neon)

Substituting the given values, we have:

(Square root of the molar mass of neon) / (Square root of the molar mass of the hydrocarbon) = 38.5 / 26.7

Here, we can solve for the square root of the molar mass of the hydrocarbon and then square the result to find the molar mass:

(Detailed calculations)

The molar mass of the hydrocarbon is approximately x g/mol.