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A disk rotates with a constant angular speed. If the speed of a point 0.7 cm from the center is 6 cm/s then what is the speed of a point located 5.3 cm from the center

User Xah Lee
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Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

To solve this problem, we can use the concept of tangential velocity in circular motion. The tangential velocity of a point on a rotating disk is directly proportional to its distance from the center of rotation.

Given:

Radius of the first point, r1 = 0.7 cm

Tangential velocity of the first point, v1 = 6 cm/s

We need to find the tangential velocity of a point located at a radius of r2 = 5.3 cm.

Using the formula for tangential velocity:

v = ω * r

where v is the tangential velocity, ω is the angular speed, and r is the radius.

Since the angular speed is constant, we can set up a proportion:

v1 / r1 = v2 / r2

Solving for v2:

v2 = (v1 * r2) / r1

Substituting the given values:

v2 = (6 cm/s * 5.3 cm) / 0.7 cm

v2 = 45.4286 cm/s

Therefore, the speed of the point located 5.3 cm from the center is approximately 45.43 cm/s.

User Visionix Visionix
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