Answer:
solution:-
let A be the assumed angle so,
AB is hypotenuse, BC is perpendicular and AC is base.
Now, By using Pythagoras theorem,
h=√ (p^2+b^2)
=√(6^2+4^2)
=√(36+16)
=2√13
since we have, hypotenuse=2√13
Then,sin A=p/h = 6/(2√13) =3/√13
cos A=b/h = 4/(2√13) =2/√13
tan A=p/b = 6/4 =3/2
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