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On a numberlinept A is at 2 and pt C is at 5 and ptB lies between A and C. What is the location of B so that the ratio of AB:BC is 1:3?

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To find the location of point B on the number line, we need to first understand that the ratio of AB:BC is 1:3. This means that the distance between A and B is one-fourth of the total distance between A and C, since 1+3=4.

To calculate the distance between A and C, we can subtract the position of A from the position of C:
distance AC = 5 - 2 = 3

Then, we can divide this distance by 4 to get the distance between A and B:
distance AB = (1/4) x 3 = 0.75

Finally, we add this distance to the position of A to find the location of B on the number line:
position B = 2 + 0.75 = 2.75

Therefore, point B is located at 2.75 on the number line.
User Christopher Causer
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