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A varies jointly as R1 and R2 and inversely as square of L. Determine A when R1=120, R2=8, L=5, and k=2

User Stiivi
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1 Answer

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To solve this problem, we can use the formula for joint variation, which states that A varies jointly as R1 and R2 if A = k*R1*R2, where k is a constant of variation.

Additionally, we know that A varies inversely as the square of L, which means that A = k*R1*R2/L^2.

Plugging in the given values, we get:
A = k*R1*R2/L^2
A = 2*120*8/5^2
A = 3.84

Therefore, when R1=120, R2=8, L=5, and k=2, A is equal to 3.84.
User Mark Staff
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