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What is the coefficient for Ag when the following equation is properly balanced? Ag + H2S + O2 → Ag2S + H2O

User AfterFray
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Answer:

The coefficient of Ag is 4.

Step-by-step explanation:

To find the coefficient of Ag first, we have to balance the equation.

We should write any number to the coefficient so the number of the element is the same on both sides. First start with basic elements like oxygen. You can see that there is 1 oxygen on the right-hand side and one on the left soo add a number to any one element on either side to balance it in this case add 2 to the RHS. This will make:

Ag + H2S + O2 → Ag2S + 2H2O

Now that makes the Hydrogen unbalanced on the right-hand side because there are 2 Hydrogen bonded together (2) on the LHS 2+2=4. To balance this add 2 to the hydrogen on the left-hand side, This will make:

Ag + 2H2S + O2 → Ag2S + 2H2O

Note that when we write a coefficient for example 2H2S that does not mean there is 2H2 instead it means that there are 2H2 and 2S.

So now sulfur is not balanced so add 2 ith sulphur on the RHS.

Ag + 2H2S + O2 → 2Ag2S + 2H2O

You can see on the left-hand side there is only 1 Ag and on the right-hand side there is 4 Ag so write 4 as the coefficient of Ag in the LHS.

4Ag + 2H2S + O2 → 2Ag2S + 2H2O

The coefficient of Ag is 4.

User Matheburg
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