Answer:
To find the concentration of the solute (aluminum sulfide) in the solution, we need to calculate the molarity (M) of the solution.
Molarity (M) is defined as moles of solute per liter of solution. First, we need to convert the mass of aluminum sulfide (14.7 grams) to moles using its molar mass.
The molar mass of aluminum sulfide (Al2S3) can be calculated as follows:
Molar mass of Al = 26.98 g/mol
Molar mass of S = 32.06 g/mol
Molar mass of Al2S3 = (2 * Molar mass of Al) + (3 * Molar mass of S)
Molar mass of Al2S3 = (2 * 26.98 g/mol) + (3 * 32.06 g/mol)
Molar mass of Al2S3 = 53.96 g/mol + 96.18 g/mol
Molar mass of Al2S3 = 150.14 g/mol
Now, we can convert the mass of aluminum sulfide to moles:
Number of moles = Mass / Molar mass
Number of moles = 14.7 g / 150.14 g/mol ≈ 0.0979 moles
Next, we calculate the molarity (M) of the solution using the volume of water (17.6 L):
Molarity (M) = Number of moles / Volume in liters
Molarity (M) = 0.0979 moles / 17.6 L ≈ 0.00556 moles/L
So, the molarity of the aluminum sulfide solution is approximately 0.00556 moles per liter (0.00556 M).