How would you go about solving (2-x)/(x^(2)+4x-12 ) ?

asked Oct 27, 2024 24.2k views

2 votes

How would you go about solving
(2-x)/(x^(2)+4x-12 )

by Pykih

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$(2-x)/(x^2+4x-12)=-(x-2)/(x^2-2x+6x-12)=-(x-2)/(x(x-2)+6(x-2))=\\\\=-(x-2)/((x-2)(x+6))=-(1)/(x+6)$

G Berdal answered Nov 1, 2024

8.7k points

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