Question

The density (in g/cm3) of a gold nugget that has a

volume of 1.68 cm3 and a mass of 32.4 g is ________.
19.3
0.0184
0.0519
54.4
32.4

Answer 1

A) 19.3

Step-by-step explanation:

The density of the gold nugget can be calculated using the formula:

`\text{Density}=\frac{\text{Mass}}{\text{Volume}}`

Substituting the values given in the problem, we get:

density = 32.4 g ÷ 1.68 cm^3

Calculating this expression gives:

density = 19.2857... g/cm^3

Rounding off to the appropriate number of significant figures, the density of the gold nugget is approximately 19.3 g/cm^3. Therefore, the answer is 19.3.

Answer 2

19.29 g/cm³

Step-by-step explanation:

V = 1.68 cm³

m = 32.4 g

`\rho=(m)/(V)`

`= (32.4)/(1.68)`

`=19.29\ g/cm^3`