Question

What is the difference in the number of kJ of energy consumed

per month between a refrigeration unit that consumes 621 W and one
that consume 853 W ? (Assume 30.0 days in one month and 24.0 hours
per

Answer 1

601344 kJ/month

Step-by-step explanation:

Watt = Joule/second

difference in energy = 853 - 621

= 232 W

= 232 J/s

= (232 × 3600) J/hr

= (835200 × 24) J/day

= (20044800 × 30) J/month

= (601344000 ÷ 1000) kJ/month

= 601344 kJ/month