Final answer:
To estimate ΔH°rxn for the reaction XeF2 + 2 F2 → XeF6, use the bond energies provided. The estimated ΔH°rxn is approximately 324 kJ/mol.
Step-by-step explanation:
To estimate the standard enthalpy change (ΔH°rxn) for the reaction XeF2 + 2 F2 → XeF6, we can use the bond energies of the bonds being broken and formed.
The bond energy of the Xe-F bond is 147 kJ/mol, and the bond energy of the F-F bond is 159 kJ/mol.
So, the energy required to break the bonds on the reactant side is 147 kJ/mol for each Xe-F bond and 159 kJ/mol for each F-F bond. On the product side, the energy released from forming Xe-F bonds will be the same as breaking them, which is 147 kJ/mol, but since 2 F-F bonds are formed the energy released will be 2 times 159 kJ/mol.
Therefore, ΔH°rxn ≈ (2 × 159 kJ/mol) - (2 × 147 kJ/mol) = 324 kJ/mol. Thus, the estimated standard enthalpy change for the reaction is approximately 324 kJ/mol.