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A LINE INTERSECTS THE POINTS (6, -4) AND (7, 4)

User HienPham
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Answer:

To find the equation of a line that intersects the points (6 -4) and (7 4 we can use the slope-intercept form of a linear equation which is y = mx + b.

First let's find the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Using the coordinates (6 -4) and (7 4 we have:

m = (4 - (-4)) / (7 - 6)

m = 8/1

m = 8

Now that we have the slope we can proceed to find the y-intercept (b). We can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

Using the point (6 -4) and the slope (m = 8 we have:

y - (-4) = 8(x - 6)

y + 4 = 8(x - 6)

y + 4 = 8x - 48

Now let's simplify the equation:

y = 8x - 52

Therefore the equation of the line that intersects the points (6 -4) and (7 4) is y = 8x - 52.

User Vanyochek
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