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Directricies of the hyperbola x^2-y^2=4

User Arney
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Answer:

Hi,

Explanation:

In the hyperbola


(x^2)/(a^2) -(y^2)/(b^2) =1


Directrix\ are\ \\x=(a^2)/(c) \\and\\x=-(a^2)/(c) \\where\ c=√(a^2+b^2) \\--------------------------------------\\Here\ a^2=4\ and\ b^2=4,\\\\c=√(4+4)=2√(2) \\\\directrix\ are\ \\x=(4)/(2√(2) ) \ or \ x=√(2) \\\ and\\x=-√(2) \\

User Thatisvaliant
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