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A 200 N force is applied at an angle of 45 to the horizontal to

move a 10 kg block at a constant velocity. The box is moved a
distance 10 m. Determine the amount of work done.

1 Answer

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Answer:

The amount of work done to move the 10 kg block at a constant velocity over a distance of 10 m with a 200 N force at an angle of 45 degrees to the horizontal is approximately 1414.2 Joules.

Step-by-step explanation:

To determine the amount of work done, we can use the formula for work:

Work (W) = Force (F) × Distance (d) × cos(θ),

where:

Force (F) is the applied force,

Distance (d) is the distance the object is moved, and

θ (theta) is the angle between the applied force and the direction of motion.

Given:

Force (F) = 200 N

Distance (d) = 10 m

Angle (θ) = 45 degrees

We first need to convert the angle from degrees to radians, as trigonometric functions in most programming languages use radians:

θ (in radians) = 45 degrees × (π/180 degrees)

θ (in radians) = 45 × (π/180) ≈ 0.7854 radians

Now, we can calculate the amount of work done:

Work (W) = 200 N × 10 m × cos(0.7854)

Using a calculator:

Work (W) ≈ 200 N × 10 m × 0.7071

Work (W) ≈ 1414.2 Joules

So, the amount of work done to move the 10 kg block at a constant velocity over a distance of 10 m with a 200 N force at an angle of 45 degrees to the horizontal is approximately 1414.2 Joules.

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