Question

A rod 16.0 cm long is uniformly charged and has a total charge of −21.0μC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 42.0 cm from its center. magnitude N/C direction

Answer 1

To determine the magnitude and direction of the electric field along the axis of the rod at a point 42.0 cm from its center, we can use the formula for the electric field due to a uniformly charged rod

Step-by-step explanation:

To determine the magnitude and direction of the electric field along the axis of the rod at a point 42.0 cm from its center, we can use the formula for the electric field due to a uniformly charged rod:

E = (k * Q * d) / (L * r)

where E is the electric field, k is the electrostatic constant, Q is the total charge, d is the distance from the center, L is the length of the rod, and r is the distance along the axis of the rod. Plugging in the given values, the magnitude of the electric field is approximately 2.31 N/C and it points towards the center of the rod.