Final answer:
To construct a 95% confidence interval for the population proportion, we can use the formula: Lower Bound = sample proportion - margin of error, Upper Bound = sample proportion + margin of error. Using x = 60 and n = 300, the sample proportion is 0.2. The critical value associated with a 95% confidence level is approximately 1.96. Using the standard error formula, we find the standard error to be approximately 0.0237. The margin of error is then calculated to be approximately 0.0466. Therefore, the 95% confidence interval for the population proportion is approximately (0.1534, 0.2466).
Step-by-step explanation:
To construct a confidence interval for a population proportion, we can use the formula:
Lower Bound = sample proportion - margin of error
Upper Bound = sample proportion + margin of error
Given that we have x = 60 successes out of n = 300 trials, the sample proportion is x/n = 60/300 = 0.2.
The margin of error can be calculated as:
Margin of Error = critical value * standard error
Since we have a 95% confidence interval, we need to find the critical value associated with a 95% confidence level.
Using the table of critical values, we find that the critical value is approximately 1.96.
The standard error is given by: √[(sample proportion * (1 - sample proportion)) / n]
Plugging in the values, the standard error is √[(0.2 * (1 - 0.2)) / 300] = √(0.00056) ≈ 0.0237.
Now, we can calculate the margin of error: Margin of Error = 1.96 * 0.0237 ≈ 0.0466.
Finally, we can construct the confidence interval using the formula:
Lower Bound = 0.2 - 0.0466 ≈ 0.1534
Upper Bound = 0.2 + 0.0466 ≈ 0.2466
Therefore, the 95% confidence interval for the population proportion is approximately (0.1534, 0.2466).