Final answer:
To find the points on the ellipse 5x² + y² = 5 that are farthest away from the point (1, 0), we can take the derivative of the equation and solve for x. The points (0, √(5)) and (0, -√(5)) have the largest and smallest y-values on the ellipse, respectively.
Step-by-step explanation:
To find the points on the ellipse 5x² + y² = 5 that are farthest away from the point (1, 0), we can start by expressing the equation in terms of y. Rearranging the equation, we get y = √(5 - 5x²), which represents the upper half of the ellipse.
The farthest points away from the point (1, 0) will be the points on the ellipse with the largest y-values. To find these points, we can take the derivative of y with respect to x, set it equal to zero, and solve for x.
Taking the derivative of y with respect to x, we get dy/dx = (-10x)/√(5 - 5x²). Setting this equal to zero, we have -10x = 0. Solving for x, we get x = 0.
Substituting x = 0 into the equation y = √(5 - 5x²), we get y = √5.
Therefore, the point (0, √5) is on the ellipse and has the largest y-value. The point (-0, -√5) is also on the ellipse and has the smallest y-value.