Question

The fundamental equation of the system A is expressed as

S=(R2/vo​θ​)^(1/3) (NVU)^(1/3)
It is similar about the system B. The two systems are separated by an adiabatic rigid wall through which a material cannot pass. The volume and the molar number of the system A is 9×10^−6 m³ and 3 mol, respectively. For the system B, they are 4×10^−6 m3 and 2 mol, respectively. A total energy of the composite system is 80 J. Illustrate entropy as a function of UA​/(UA​+UB​). In addition, how much is the internal energy of each ingredient system when an inner wall is changed to be a diabatic wall and the composite system becomes an equilibrium state? (Similar to the problem [1], v0​,θ,R are positive constants.)

Answer 1

The fundamental equation of the system A is expressed. We can calculate the values of the equation using the given volumes and molar numbers. To illustrate entropy, we need to find the values of U for each ingredient system when the inner wall is changed.

Step-by-step explanation:

The fundamental equation of the system A is given by: \(S = \left(\frac{R^2}{v_0\theta}\right)^{1/3}(NVU)^{1/3}\)

Given the volumes and the molar numbers of systems A and B, we can calculate the values of the equation.

To illustrate entropy as a function of \(\frac{UA}{UA+UB}\), we need to find the values of U for each ingredient system when the inner wall is changed to be a diabatic wall and the composite system reaches equilibrium.