Question

A young kid of mass m = 28 kg is swinging on a swing. The length from the top of the swing set to the seat is L = 4.9 m. The child is attempting to swing all the way around in a full circle.

v=6.93 (from part a)
Wa=0
If the velocity at the bottom is the same as the velocity at the top from part (a), what is the child's apparent weight, in newtons, at the very bottom of the path?
Wa2=

Answer 1

The apparent weight of the child at the very bottom of the path is 0.03 N.

How to calculate the child's apparent weight?

The apparent weight of the child is calculated by applying the following formula as shown below;

W' = Fc - W

W' = mv²/r - mg

where;

• m is the mass of the child
• v is the speed of the child
• r is the radius of the circular path
• g is acceleration due to gravity

The apparent weight of the child is calculated as follows;

W' = (28 kg x (6.93 m/s)² )/ (4.9 m) - (28 kg x 9.8 m/s²)

W' = 274.43 N - 274.4 N

W' = 0.03 N

Thus, the apparent weight of the child at the very bottom of the path is approximately zero Newton.