Question

a 14 cm long metal rod is oriented horizontally in a uniform magnetic field with magnetic flux density of 486 g. the magnetic field is directed vertically down into the ground. a current of 28 a is passed through the rod. neglect the magnetic field of earth at the location of this apparatus. determine the magnitude of magnetic force on the rod in the units of n. write your answer in decimal form with three digits to the right of the decimal point (e.g. 5.374); do not write any units

Answer 1

To determine the magnitude of the magnetic force on the metal rod, we can use the formula F = BIL, where B is the magnetic flux density, I is the current, and L is the length of the rod. Plugging in the given values, we find that the magnitude of the magnetic force is approximately 1.942 N.

Step-by-step explanation:

To find the magnitude of the magnetic force on the rod, we can use the formula F = BIL, where F is the force, B is the magnetic flux density, I is the current, and L is the length of the rod. In this case, B = 486 G (0.486 T), I = 28 A, and L = 14 cm (0.14 m). Plugging in these values, we get F = (0.486 T)(28 A)(0.14 m) = 1.9416 N. Therefore, the magnitude of the magnetic force on the rod is approximately 1.942 N.

Answer 2

The magnitude of the magnetic force on the 14 cm long metal rod is 1.036 N.

Step-by-step explanation:

To determine the magnitude of the magnetic force on the rod, we can use the formula F = BILsinθ, where F is the force, B is the magnetic flux density, I is the current, L is the length of the rod, and θ is the angle between the magnetic field and the direction of the current. In this case, the magnetic field is directed vertically down into the ground, so the angle θ is 90 degrees.

Plugging in the values, we have F = (486 g)(28 A)(14 cm)(sin 90°). Converting grams to kilograms and centimeters to meters, we get F = (0.486 kg)(28 A)(0.14 m) = 1.036 N.

Therefore, the magnitude of the magnetic force on the rod is 1.036 N.