Question

suppose the wavelength of the light is 480 nm . how much farther is it from the dot on the screen in the center of fringe e to the left slit than it is from the dot to the right slit?

Answer 1

The distance from the dot to the left slit is not farther than the distance to the right slit in a double-slit interference experiment.

Step-by-step explanation:

In a double-slit interference experiment, the distance between the dot on the screen in the center of fringe e and the left slit is equal to the distance between the dot and the right slit. This is because both slits are equidistant from the center of the fringe, resulting in the same path length for the light to reach the dot. Therefore, the distance from the dot to the left slit is not farther than the distance to the right slit.

Answer 2

The question is about calculating the path difference in a double-slit light interference experiment, which forms the fringe pattern on the screen. Without additional data on the fringe order or position, we assume the first-order maximum, where the path difference would be equal to the given wavelength of 480 nm.

Step-by-step explanation:

The question involves a concept from Physics known as interference in light. Specifically, it concerns the path difference in a double-slit experiment, which leads to the creation of a fringe pattern on the screen placed behind the slits. Given the wavelength of the light, we can calculate the path difference necessary for constructive and destructive interference, which forms the bright and dark fringes, respectively.

If we are talking about the path difference for a particular fringe (labeled 'e'), which is a bright fringe, we would be looking for a multiple of the wavelength, signaling constructive interference. The path difference between the left and right slit to a specific fringe on the screen would therefore be a multiple of the wavelength of the light used. If fringe 'e' is a bright fringe, it could be the central fringe (zero-order maximum) or any other higher-order maximum, depending on its position relative to the center.

Without more specific information about fringe 'e' in this context, such as its order number or position, we cannot calculate the exact value of the path difference. If we assume that fringe 'e' corresponds to the first-order maximum (the first bright fringe on either side of the central fringe), then the path difference would be equal to the wavelength of the light, which is 480 nm. However, if fringe 'e' is of higher order, then the path difference would be a multiple of the wavelength.