Question

p varies directly as the square of q and inversely as the cube of z, when p-5,q-3 and z-1, find the relationship between p,q and z​

Answer 1

Explanation:

Answer 2

Explanation:

p = k q^2 / z^3 k = proprtion constant <=======given...

-5 = k (-3)^2 / (-1)^3

-5 = - 9k

k = 5/9

then p = 5/9 (q^2/z^3)