Answer:
Explanation:
P(4 only on the last roll) = P(not 4 on first roll) and P(not 4 on the second roll) and P(not 4 on the third roll) and P(4 on the last roll)
in probability and = multiplication
P( not roll a 4) = 1 - P(roll a 4)
P(4 only on the last roll) = 1-P(4) * 1-P(4) *1-P(4) * P(4)
P(4) = 1 (1 time# 4 appears on the die)/6 (#of possible outcomes 1,2,3,4,5,6)
P(4 only on the last roll) = 1-(1/6) * 1-(1/6) *1-(1/6) * (1/6)
P(4 only on the last roll) =(5*5*5*1)/(6*6*6*6) = 125/1296