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4 votes
What volume does 4.53 moles of
hydrogen at 1.78 atm and 301 K
occupy?
Volume (L)

User Quent
by
7.9k points

1 Answer

2 votes

Answer:

To determine the volume we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure (in atm)

V = volume (in liters)

n = number of moles of gas

R = ideal gas constant (0.0821 L·atm/(mol·K))

T = temperature (in Kelvin)

Given:

n = 4.53 moles

P = 1.78 atm

T = 301 K

R = 0.0821 L·atm/(mol·K)

We can rearrange the equation to solve for V:

V = (n * R * T) / P

Now substituting the given values:

V = (4.53 moles * 0.0821 L·atm/(mol·K) * 301 K) / 1.78 atm

Calculating this equation we find:

V ≈ 24.0 liters

Therefore 4.53 moles of hydrogen at 1.78 atm and 301 K would occupy approximately 24.0 liters of volume.

User Khepin
by
8.6k points