Question

PLEASE HELP !

Write an equation for the function graphed below. The y intercept is at (0,-0.4)

Answer 1

Hi,

`y=-(48*(x-2)^2)/(10*(x+3)(x-4)^2)}\\`

Explanation:

1) asymptotes are x=-3 and x=4 => on denominator (x+3)(x-4)

but part 1 and 3 must be returned => -

2) in the middle: pass trough (2,0) => on numerator (x-2)

but this part is opening up => (x-2)²

3) part 3 is turning down => (x-4)²

Here we have

`y=-(k(x-2)^2)/((x+3)(x-4)^2)}\\\\\\if\ x=0,\ y=-0.4\\\\-0.4=-(k(0-2)^2)/((0+3)(0-4)^2)}\\\\k=4.8\\\\`