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Calculate the pH if [OH-] = 1.60 × 10-4 M

pleaseeee help!!!!!

User Egwspiti
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1 Answer

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[H3O] = 1x10-14/ [ OH]
= 1x10-14/1x10-4 =1x10-10 M
Ph=-log[H3O]
= _log[1x10-10]=10

I hope this helped !! Im srry if u dont lol
User Istiak Mahmood
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