8. In Diagram 3, JKR is a tangent to the circle KSTU at K.

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asked Aug 15, 2024 186k views

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8. In Diagram 3, JKR is a tangent to the circle KSTU at K.

Mathematics
high-school

Achiash asked

by Achiash

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Answer:

Hi,

Explanation:

$mes\ \widehat{RKT}=55^o+33^o=88^o=arc(KST)\\\\x^o=180^o-88^o= 92^o\\$

Answer: C

Andrey Patseiko answered Aug 21, 2024

by Andrey Patseiko

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