Question

A car is travelling at 54 km/h, it speeds up to 72 km/h in 6 seconds. What is its acceleration? ​

Answer 1

the acceleration of the car is 0.83 m/s^2.

Step-by-step explanation:

To calculate the acceleration of the car, we need to use the formula:

Acceleration = (Final velocity - Initial velocity) / Time

1. First, we convert the given velocities from km/h to m/s. To convert km/h to m/s, we divide by 3.6 (since 1 km/h = 1000 m/3600 s = 1/3.6 m/s).

Initial velocity = 54 km/h = (54/3.6) m/s = 15 m/s

Final velocity = 72 km/h = (72/3.6) m/s = 20 m/s

2. Next, we substitute the values into the formula:

Acceleration = (20 m/s - 15 m/s) / 6 s

3. We simplify the equation:

Acceleration = 5 m/s / 6 s

4. Finally, we calculate the acceleration:

Acceleration = 0.83 m/s^2

Therefore, the acceleration of the car is 0.83 m/s^2.

Answer 2

It's acceleration is 0.833 m/s²

Step-by-step explanation:

Given information:

• Initial velocity (u) = 54 km/h=
  `\sf (54*1000)/(1*60*60)` = 15 m/s
• Final velocity (v) = 72 km/h =
  `\sf (72*1000)/(1*60*60)` = 20m/s
• Time taken (t) = 6 seconds

To find:

• Acceleration due to gravity(a) =?

Solution:

The acceleration of the car can be calculated using the following formula:

`\boxed{\sf v = u + at}`

Where:

• v is the final velocity of the car (in m/s)
• u is the initial velocity of the car (in m/s)
• a is the acceleration of the car (in m/s²)
• t is the time taken (in seconds)

Substituting Value

20 = 15 +a*6

20 = 15 +6a

Subtracting both side by 15.

20-15 = 15+6a -15

5 = 6a

Dividing both sides by 6.

`\sf (5)/(6)=(6a)/(6)`

`\sf a = (5)/(6)\approx 0.833`

Therefore, the acceleration of the car is approximately 0.8333 meters per second squared (m/s²).