Final Answer:
The median is the better measure of the "center" in this scenario.
Step-by-step explanation:
In this small town with 50 residents, the mean and median are two statistical measures that provide insights into the central tendency of income distribution. The mean, or average, is calculated by summing up all incomes and dividing by the number of people. In this case, the mean income would be calculated as:
[ text{Mean} = frac{Sigma text{Income}}{text{Number of People}} ]
Substituting the values, we get:
[ text{Mean} = frac{(1 times 5,000,000) + (49 times 30,000)}{50} ]
After calculating, the mean income turns out to be $125,800. While the mean provides a single numerical representation of income, it can be heavily influenced by extreme values, such as the $5,000,000 income in this case. This extreme value significantly skews the mean higher than the majority of incomes.
On the other hand, the median is the middle value when all incomes are arranged in ascending order. In this scenario, the median income would be $30,000, as it falls right in the middle when the incomes are sorted. The median is less sensitive to extreme values and provides a better representation of the typical income in the town. Therefore, in situations with skewed distributions like this, the median is a more reliable measure of central tendency.