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For the system of linear equations

{3x+2y=m+1
{x+4y=5m-1
with respect to x and y, the solution satisfies x

User Ecs
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If we have 3 unknowns, there should be 3 simultaneous equations available, so I’m going to treat m as a constant. Subtracting equation 2 with double the equation 1 will obtain => -5x = 3m-3 so x = (3m-3)/5. Then rearranging to y (using equation 1), we get =>y = (m+1-3x)/2. Substituting in x we worked out will give y = (-8m+10)/2 => y = (5-4m)/2
User Lodkkx
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