Answer:
Approximately 1040 of $10 tickets were sold.
Explanation:
Assume the number of $10 tickets sold is "x".
According to the information provided:
The team sells three types of tickets: $10, $20, and VIP ($30).
The total number of tickets sold is 3147.
The team has sold 211 more $20 tickets than $10 tickets.
The total sales are $61,130.
We can set up equations based on the information given:
Total number of tickets sold:
x (number of $10 tickets) + (x + 211) (number of $20 tickets) + (number of VIP tickets) = 3147
Total sales:
$10 * x + $20 * (x + 211) + $30 * (number of VIP tickets) = $61,130
We can solve the equations to find the values of "x" and the number of VIP tickets:
Total number of tickets sold equation:
x + (x + 211) + (number of VIP tickets) = 3147
2x + 211 + (number of VIP tickets) = 3147
2x + (number of VIP tickets) = 3147 - 211
2x + (number of VIP tickets) = 2936
Total sales equation:
$10 * x + $20 * (x + 211) + $30 * (number of VIP tickets) = $61,130
$10 * x + $20x + $20 * 211 + $30 * (number of VIP tickets) = $61,130
$10 * x + $20x + $4220 + $30 * (number of VIP tickets) = $61,130
$30x + $30 * (number of VIP tickets) = $61,130 - $4220
$30x + $30 * (number of VIP tickets) = $56,910
Now, we have a system of two equations:
2x + (number of VIP tickets) = 2936
$30x + $30 * (number of VIP tickets) = $56,910
We can solve this system of equations to find the value of "x" (number of $10 tickets) and the number of VIP tickets. Let's do that:
Solve equation 1 for "number of VIP tickets":
(number of VIP tickets) = 2936 - 2x
Substitute the value of (number of VIP tickets) from equation 1 into equation 2:
$30x + $30 * (2936 - 2x) = $56,910
Now, solve for "x":
$30x + $30 * 2936 - $30 * 2x = $56,910
$30x + $88,080 - $60x = $56,910
-$30x = $56,910 - $88,080
-$30x = -$31,170
Divide both sides by -30:
x = $31,170 / $30
x = 1040.5
Since we can't have half a ticket, let's round down to the nearest whole number:
x ≈ 1040
So, approximately 1040 of $10 tickets were sold.