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An envelope is of length 21cm and breadth 11 cm. What is the maximum and minimum area of the envelope, if it's dimensions are correct to the nearest centimeter.

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To find the maximum and minimum area of the envelope, we need to consider the possible variations in its dimensions due to rounding to the nearest centimeter.

Given:

Length = 21 cm (correct to the nearest centimeter)

Breadth = 11 cm (correct to the nearest centimeter)

Maximum area:

If the dimensions are correct to the nearest centimeter, the actual dimensions could be up to 0.5 cm more than the given values (21.5 cm for length and 11.5 cm for breadth) to round up.

Area (maximum) = Length * Breadth

Area (maximum) = 21.5 cm * 11.5 cm

Area (maximum) ≈ 247.25 square centimeters

Minimum area:

Similarly, if the dimensions are correct to the nearest centimeter, the actual dimensions could be up to 0.5 cm less than the given values (20.5 cm for length and 10.5 cm for breadth) to round down.

Area (minimum) = Length * Breadth

Area (minimum) = 20.5 cm * 10.5 cm

Area (minimum) ≈ 215.25 square centimeters

So, the maximum area of the envelope (correct to the nearest centimeter) is approximately 247.25 square centimeters, and the minimum area is approximately 215.25 square centimeters.

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