Question

Find a:
S = ut + 1/2 at^2
S = 80, U = 10, T = 4

Answer 1

Given to us:—

• S = ut +1/2 at² ; S = 80 , U = 10 , T = 4

To find:—

• the value of a

`\hrulefill`

`\rightleftharpoons\sf{S=ut+\cfrac{1}{2}at^2}`

`\rightleftharpoons\sf{80=10*4+\cfrac{1}{2}a*4^2}`

`\rightleftharpoons\sf{80=40+\cfrac{1}{2}a*16}`

`\rightleftharpoons\sf{80-40=\cfrac{1}{2}a*16}`

`\rightleftharpoons\sf{40=\cfrac{1}{2}a*16}`

`\rightleftharpoons\sf{40=\cfrac{1}{2}a*\cfrac{16}{1}`

`\rightleftharpoons\sf{40=8a}`

`\rightleftharpoons\sf{5=a}`

Henceforth, a = 5 .

Answer 2

To find the value of "a" in the equation S = ut + 1/2 at^2, we can plug in the given values and solve for "a".

Given:

S = 80

U = 10

T = 4

Substitute the values into the equation:

80 = (10 * 4) + 1/2 * a * 4^2

Now, simplify the equation:

80 = 40 + 2a

Next, isolate "a" by subtracting 40 from both sides of the equation:

2a = 80 - 40

2a = 40

Finally, divide both sides by 2 to solve for "a":

a = 40 / 2

a = 20

So, the value of "a" is 20.