Answer:
length = 16 m , perimeter = 56 m
Explanation:
let l be length then width = l - 16
area (A) is calculated as
A = length × width
= l(l - 16)
given A = 132 , then
l(l - 16) = 132
l² - 16l = 132 ( subtract 132 from both sides )
l² - 16l - 132 = 0 ← quadratic in standard form
(l - 22)(l + 6) = 0 ← in factored form
equate each factor to zero and solve for l
l - 22 = 0 ⇒ l = 22
l + 6 = 0 ⇒ l = - 6
however, l > 0 , then l = 22 and w = l - 16 = 22 - 16 = 6
the length of the hall is 22 m , width is 6 m
the perimeter (P) of a rectangle is calculated as
P = 2 (length + width)
= 2(22 + 6)
= 2 × 28
= 56 m