Question

Fatima is preparing food parcels to give to charity.

She has 252 tins of beans, 168 chocolate bars and 294 packets of soup. Each food parcel must contain the same, and there must be nothing left over. What is the greatest number of parcels she can prepare, and what will be in each parcel

Answer 1

42

Each parcel would contain 6 tins of beans, 4 chocolate bars and 7 packets of soup.

Explanation:

The GCF would be 42

Each parcel would contain 6 tins of beans, 4 chocolate bars and 7 packets of soup.

252 =
`2^(2)` ·
`3^(2)` · 7

168 =
`2^(2)` · 3 ·
`7^(2)`

294 =
`2^(2)`· 3 · 7

Answer 2

To find the greatest number of food parcels Fatima can prepare, we need to determine the greatest common divisor (GCD) of the quantities of each item (tins of beans, chocolate bars, and packets of soup).

GCD(252, 168, 294) = 42

The greatest number of food parcels she can prepare is 42. Now, let's calculate what will be in each parcel.

Number of tins of beans per parcel = 252 / 42 = 6

Number of chocolate bars per parcel = 168 / 42 = 4

Number of packets of soup per parcel = 294 / 42 = 7

Therefore, each food parcel will contain 6 tins of beans, 4 chocolate bars, and 7 packets of soup.