Question

Pls help its timed to yea and here's the text version (Experimental Probability MC)

A spinner is divided into three equal parts A, B, and C. The repeated experiment of spinning the spinner twice is simulated 125 times. A table of outcomes is shown.


Outcome Frequency
A, A 15
A, B 12
A, C 10
B, A 18
B, B 15
B, C 17
C, A 11
C, B 13
C, C 14

Based on the table, for what probability can you expect the spinner to not land on A?
0.66
0.47
0.33
0.10

Answer 1

0.47

Explanation:

given that the outcome frequency for A is approximately 66 out of 125

we can do 66/125 to get the frequency of A

66/125 = 0.528

subtract that from 1 in order to get the frequency of not spinning A

1 - 0.528 = 0.472

round to nearest

0.472 --> 0.47