Question

In the diagram, AB is parallel to CD and EFGH is a straight line. Find the value of x​

Answer 1

In the diagram, AB is parallel to CD and EFGH is a straight line.

A^FG is a flat angle = 180°

B^FG+A^FH = 180°

B^FG +4x-34=180°

B^FG = (214-4x)°

B^FG is alternate-internal with C^GH the angles are equal(If two lines d and d′ are parallel, then the alternate-internal angles defined by a secant are equal.)

(214-4x)°=(2x-2)²

-4x-2x=-2-214

-6x=-216

x=36°

Answer 2

x = 36°

Explanation:

(4x - 34) + (2x - 2) = 180° because co interior angles add up to 180° and angles on a straight line add up to 180°

4x - 34 + 2x - 2 = 180°

Add/subtract like terms (4x + 2x), (-34 - 2)

6x - 36 = 180°

+36 to both sides

6x = 216°

÷6 from both sides

x = 36°